Proof 01. 1 ⊢ x ∈ ∅, hypo. 02. 1 ⊢ x ∈ {x | ⊥}, eq_subst empty_set_eq 1. 03. 1 ⊢ ⊥, comp_elim 2. empty_contra. ⊢ x ∈ ∅ → ⊥, subj_intro 3.
DependenciesThe given proof depends on two axioms:comp, eq_subst.